y^3-3y^2=4y+12

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Solution for y^3-3y^2=4y+12 equation: 


Simplifying
y3 + -3y2 = 4y + 12

Reorder the terms:
-3y2 + y3 = 4y + 12

Reorder the terms:
-3y2 + y3 = 12 + 4y

Solving
-3y2 + y3 = 12 + 4y

Solving for variable 'y'.

Reorder the terms:
-12 + -4y + -3y2 + y3 = 12 + 4y + -12 + -4y

Reorder the terms:
-12 + -4y + -3y2 + y3 = 12 + -12 + 4y + -4y

Combine like terms: 12 + -12 = 0
-12 + -4y + -3y2 + y3 = 0 + 4y + -4y
-12 + -4y + -3y2 + y3 = 4y + -4y

Combine like terms: 4y + -4y = 0
-12 + -4y + -3y2 + y3 = 0

The solution to this equation could not be determined.

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